Base | Representation |
---|---|
bin | 100011011111001000101001… |
… | …0111010111111110000010111 |
3 | 1111221012112011221110222011222 |
4 | 1012332101102322333300113 |
5 | 311403120201201320203 |
6 | 3023512131005520555 |
7 | 122514355340104562 |
oct | 10676212272776027 |
9 | 1457175157428158 |
10 | 312142434401303 |
11 | 90504954757170 |
12 | 2b01336587315b |
13 | 10522b9cb2871c |
14 | 5711abb0994d9 |
15 | 261481b070038 |
hex | 11be452ebfc17 |
312142434401303 has 16 divisors (see below), whose sum is σ = 355324867402752. Its totient is φ = 271427689500000.
The previous prime is 312142434401293. The next prime is 312142434401311. The reversal of 312142434401303 is 303104434241213.
It is not a de Polignac number, because 312142434401303 - 212 = 312142434397207 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (312142434401333) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 202835453 + ... + 204368553.
It is an arithmetic number, because the mean of its divisors is an integer number (22207804212672).
Almost surely, 2312142434401303 is an apocalyptic number.
312142434401303 is a deficient number, since it is larger than the sum of its proper divisors (43182433001449).
312142434401303 is a wasteful number, since it uses less digits than its factorization.
312142434401303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2337886.
The product of its (nonzero) digits is 82944, while the sum is 35.
Adding to 312142434401303 its reverse (303104434241213), we get a palindrome (615246868642516).
The spelling of 312142434401303 in words is "three hundred twelve trillion, one hundred forty-two billion, four hundred thirty-four million, four hundred one thousand, three hundred three".
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