Base | Representation |
---|---|
bin | 101101011011100110011… |
… | …010101001001101101011 |
3 | 102001110110101101010121222 |
4 | 231123212122221031223 |
5 | 402122340033014011 |
6 | 10350122120052255 |
7 | 441362240104022 |
oct | 55334632511553 |
9 | 12043411333558 |
10 | 3122012001131 |
11 | aa4046425051 |
12 | 42509760408b |
13 | 198534803c8a |
14 | ab16b53d8b9 |
15 | 5632617cddb |
hex | 2d6e66a936b |
3122012001131 has 4 divisors (see below), whose sum is σ = 3122018134032. Its totient is φ = 3122005868232.
The previous prime is 3122012001067. The next prime is 3122012001161. The reversal of 3122012001131 is 1311002102213.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3122012001131 - 26 = 3122012001067 is a prime.
It is a super-2 number, since 2×31220120011312 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3122012001161) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2226095 + ... + 3346568.
It is an arithmetic number, because the mean of its divisors is an integer number (780504533508).
Almost surely, 23122012001131 is an apocalyptic number.
3122012001131 is a deficient number, since it is larger than the sum of its proper divisors (6132901).
3122012001131 is an equidigital number, since it uses as much as digits as its factorization.
3122012001131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6132900.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 3122012001131 its reverse (1311002102213), we get a palindrome (4433014103344).
The spelling of 3122012001131 in words is "three trillion, one hundred twenty-two billion, twelve million, one thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •