Base | Representation |
---|---|
bin | 1001000101100001010… |
… | …10010011001110110001 |
3 | 1002211211212020200020210 |
4 | 10202300222103032301 |
5 | 20103342042233040 |
6 | 355231242054333 |
7 | 31361434112130 |
oct | 4426052231661 |
9 | 1084755220223 |
10 | 312201524145 |
11 | 110449691a55 |
12 | 5060b7aa3a9 |
13 | 23595962394 |
14 | 1117981b917 |
15 | 81c398a480 |
hex | 48b0a933b1 |
312201524145 has 32 divisors (see below), whose sum is σ = 571668185088. Its totient is φ = 142524347328.
The previous prime is 312201524083. The next prime is 312201524233. The reversal of 312201524145 is 541425102213.
It is not a de Polignac number, because 312201524145 - 211 = 312201522097 is a prime.
It is a super-3 number, since 3×3122015241453 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1968609 + ... + 2121278.
It is an arithmetic number, because the mean of its divisors is an integer number (17864630784).
Almost surely, 2312201524145 is an apocalyptic number.
312201524145 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
It is an amenable number.
312201524145 is a deficient number, since it is larger than the sum of its proper divisors (259466660943).
312201524145 is a wasteful number, since it uses less digits than its factorization.
312201524145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4090629.
The product of its (nonzero) digits is 9600, while the sum is 30.
Adding to 312201524145 its reverse (541425102213), we get a palindrome (853626626358).
The spelling of 312201524145 in words is "three hundred twelve billion, two hundred one million, five hundred twenty-four thousand, one hundred forty-five".
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