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312211313041 is a prime number
BaseRepresentation
bin1001000101100010011…
…11101001000110010001
31002211212112200000002111
410202301033221012101
520103402044004131
6355232231545321
731361613242155
oct4426117510621
91084775600074
10312211313041
11110454168551
1250612b2b241
13235979abb24
141117ac49065
1581c4770ab1
hex48b13e9191

312211313041 has 2 divisors, whose sum is σ = 312211313042. Its totient is φ = 312211313040.

The previous prime is 312211313039. The next prime is 312211313053. The reversal of 312211313041 is 140313112213.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 188250986641 + 123960326400 = 433879^2 + 352080^2 .

It is an emirp because it is prime and its reverse (140313112213) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 312211313041 - 21 = 312211313039 is a prime.

Together with 312211313039, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (312211313081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156105656520 + 156105656521.

It is an arithmetic number, because the mean of its divisors is an integer number (156105656521).

Almost surely, 2312211313041 is an apocalyptic number.

It is an amenable number.

312211313041 is a deficient number, since it is larger than the sum of its proper divisors (1).

312211313041 is an equidigital number, since it uses as much as digits as its factorization.

312211313041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 312211313041 its reverse (140313112213), we get a palindrome (452524425254).

The spelling of 312211313041 in words is "three hundred twelve billion, two hundred eleven million, three hundred thirteen thousand, forty-one".