Base | Representation |
---|---|
bin | 100011011111101000101110… |
… | …0011011001100000101101111 |
3 | 1111221110002222020022011210122 |
4 | 1012333101130123030011233 |
5 | 311410232232201441421 |
6 | 3024003521451555155 |
7 | 122522344252144613 |
oct | 10677213433140557 |
9 | 1457402866264718 |
10 | 312211313312111 |
11 | 9053109003a344 |
12 | 2b02478915babb |
13 | 10529528c1a295 |
14 | 5715172c43343 |
15 | 26164ed0312ab |
hex | 11bf45c6cc16f |
312211313312111 has 2 divisors, whose sum is σ = 312211313312112. Its totient is φ = 312211313312110.
The previous prime is 312211313312089. The next prime is 312211313312113. The reversal of 312211313312111 is 111213313112213.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 312211313312111 - 226 = 312211246203247 is a prime.
Together with 312211313312113, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312211313312113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156105656656055 + 156105656656056.
It is an arithmetic number, because the mean of its divisors is an integer number (156105656656056).
Almost surely, 2312211313312111 is an apocalyptic number.
312211313312111 is a deficient number, since it is larger than the sum of its proper divisors (1).
312211313312111 is an equidigital number, since it uses as much as digits as its factorization.
312211313312111 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 648, while the sum is 26.
Adding to 312211313312111 its reverse (111213313112213), we get a palindrome (423424626424324).
The spelling of 312211313312111 in words is "three hundred twelve trillion, two hundred eleven billion, three hundred thirteen million, three hundred twelve thousand, one hundred eleven".
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