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31223344431142 = 215611672215571
BaseRepresentation
bin1110001100101110000000…
…10110101000000000100110
311002112220220120001211202101
413012113000112220000212
513043030402133244032
6150223450104002314
76401545403443243
oct706270026500046
9132486816054671
1031223344431142
119a48822a38846
123603362a6039a
13145646c26c606
1479d30a0205ca
153922ce15cde7
hex1c65c05a8026

31223344431142 has 4 divisors (see below), whose sum is σ = 46835016646716. Its totient is φ = 15611672215570.

The previous prime is 31223344431137. The next prime is 31223344431193. The reversal of 31223344431142 is 24113444332213.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×312233444311422 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7805836107784 + ... + 7805836107787.

It is an arithmetic number, because the mean of its divisors is an integer number (11708754161679).

Almost surely, 231223344431142 is an apocalyptic number.

31223344431142 is a deficient number, since it is larger than the sum of its proper divisors (15611672215574).

31223344431142 is a wasteful number, since it uses less digits than its factorization.

31223344431142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15611672215573.

The product of its digits is 165888, while the sum is 37.

Adding to 31223344431142 its reverse (24113444332213), we get a palindrome (55336788763355).

The spelling of 31223344431142 in words is "thirty-one trillion, two hundred twenty-three billion, three hundred forty-four million, four hundred thirty-one thousand, one hundred forty-two".

Divisors: 1 2 15611672215571 31223344431142