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312300012210120 = 23325112329293403537
BaseRepresentation
bin100011100000010010000001…
…1010010101000011111001000
31111221202120220210221001112100
41013000210003102220133020
5311413210411111210440
63024112351153113400
7122531634302301114
oct10700440322503710
91457676823831470
10312300012210120
1190565767280230
122b039a02258860
13105349c3309b0c
145719589014744
152618990051230
hex11c09034a87c8

312300012210120 has 768 divisors, whose sum is σ = 1199309770713600. Its totient is φ = 69681434296320.

The previous prime is 312300012210101. The next prime is 312300012210161. The reversal of 312300012210120 is 21012210003213.

312300012210120 is a `hidden beast` number, since 31 + 2 + 300 + 0 + 1 + 2 + 210 + 120 = 666.

It is a super-2 number, since 2×3123000122101202 (a number of 30 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 312300012210093 and 312300012210102.

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 773704992 + ... + 774108528.

It is an arithmetic number, because the mean of its divisors is an integer number (1561601263950).

Almost surely, 2312300012210120 is an apocalyptic number.

312300012210120 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 312300012210120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (599654885356800).

312300012210120 is an abundant number, since it is smaller than the sum of its proper divisors (887009758503480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

312300012210120 is a wasteful number, since it uses less digits than its factorization.

312300012210120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 403910 (or 403903 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 312300012210120 its reverse (21012210003213), we get a palindrome (333312222213333).

The spelling of 312300012210120 in words is "three hundred twelve trillion, three hundred billion, twelve million, two hundred ten thousand, one hundred twenty".