Base | Representation |
---|---|
bin | 101101011100100010101… |
… | …001001100110101111011 |
3 | 102001120001210201020221202 |
4 | 231130202221030311323 |
5 | 402131422221400133 |
6 | 10350410253324415 |
7 | 441426256554146 |
oct | 55344251146573 |
9 | 12046053636852 |
10 | 3123022450043 |
11 | aa45148352a1 |
12 | 425319a9670b |
13 | 198665c5c142 |
14 | ab22580b05d |
15 | 56384c252e8 |
hex | 2d722a4cd7b |
3123022450043 has 2 divisors, whose sum is σ = 3123022450044. Its totient is φ = 3123022450042.
The previous prime is 3123022450003. The next prime is 3123022450109. The reversal of 3123022450043 is 3400542203213.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3123022450043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3123022449988 and 3123022450015.
It is not a weakly prime, because it can be changed into another prime (3123022450003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1561511225021 + 1561511225022.
It is an arithmetic number, because the mean of its divisors is an integer number (1561511225022).
Almost surely, 23123022450043 is an apocalyptic number.
3123022450043 is a deficient number, since it is larger than the sum of its proper divisors (1).
3123022450043 is an equidigital number, since it uses as much as digits as its factorization.
3123022450043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 29.
Adding to 3123022450043 its reverse (3400542203213), we get a palindrome (6523564653256).
The spelling of 3123022450043 in words is "three trillion, one hundred twenty-three billion, twenty-two million, four hundred fifty thousand, forty-three".
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