Base | Representation |
---|---|
bin | 1110001100111100111000… |
… | …11001010110110110010111 |
3 | 11002120200112011101202122120 |
4 | 13012132130121112312113 |
5 | 13043143231230231403 |
6 | 150231250410031023 |
7 | 6402250333150236 |
oct | 706363431266627 |
9 | 132520464352576 |
10 | 31231331102103 |
11 | 9a51151231960 |
12 | 3604a11718473 |
13 | 1457142ac6812 |
14 | 79d866a18b1d |
15 | 3925ea3c3e53 |
hex | 1c679c656d97 |
31231331102103 has 32 divisors (see below), whose sum is σ = 47402979950592. Its totient is φ = 18104934117600.
The previous prime is 31231331102093. The next prime is 31231331102123. The reversal of 31231331102103 is 30120113313213.
It is not a de Polignac number, because 31231331102103 - 25 = 31231331102071 is a prime.
It is a super-2 number, since 2×312313311021032 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31231331102123) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 116666538 + ... + 116933928.
It is an arithmetic number, because the mean of its divisors is an integer number (1481343123456).
Almost surely, 231231331102103 is an apocalyptic number.
31231331102103 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
31231331102103 is a deficient number, since it is larger than the sum of its proper divisors (16171648848489).
31231331102103 is a wasteful number, since it uses less digits than its factorization.
31231331102103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 421315.
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 31231331102103 its reverse (30120113313213), we get a palindrome (61351444415316).
The spelling of 31231331102103 in words is "thirty-one trillion, two hundred thirty-one billion, three hundred thirty-one million, one hundred two thousand, one hundred three".
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