Base | Representation |
---|---|
bin | 101101011100101001010… |
… | …000000111000011000111 |
3 | 102001120100112022200122110 |
4 | 231130221100013003013 |
5 | 402132134112010343 |
6 | 10350425253432103 |
7 | 441432104102340 |
oct | 55345120070307 |
9 | 12046315280573 |
10 | 3123133313223 |
11 | aa4571376460 |
12 | 42534b03b633 |
13 | 198682c07361 |
14 | ab2364290c7 |
15 | 5638e823833 |
hex | 2d7294070c7 |
3123133313223 has 32 divisors (see below), whose sum is σ = 5191847608320. Its totient is φ = 1622361454560.
The previous prime is 3123133313207. The next prime is 3123133313243. The reversal of 3123133313223 is 3223133313213.
It is not a de Polignac number, because 3123133313223 - 24 = 3123133313207 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3123133313243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 9044418 + ... + 9383376.
It is an arithmetic number, because the mean of its divisors is an integer number (162245237760).
Almost surely, 23123133313223 is an apocalyptic number.
3123133313223 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
3123133313223 is a deficient number, since it is larger than the sum of its proper divisors (2068714295097).
3123133313223 is a wasteful number, since it uses less digits than its factorization.
3123133313223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 378867.
The product of its digits is 17496, while the sum is 30.
Adding to 3123133313223 its reverse (3223133313213), we get a palindrome (6346266626436).
The spelling of 3123133313223 in words is "three trillion, one hundred twenty-three billion, one hundred thirty-three million, three hundred thirteen thousand, two hundred twenty-three".
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