Base | Representation |
---|---|
bin | 101101011101000110111… |
… | …011111110110011011111 |
3 | 102001121122020110201212011 |
4 | 231131012323332303133 |
5 | 402134144111244210 |
6 | 10350550524252051 |
7 | 441450332263453 |
oct | 55350673766337 |
9 | 12047566421764 |
10 | 3123631353055 |
11 | aa47a7514124 |
12 | 4254699a1027 |
13 | 198732154195 |
14 | ab282630663 |
15 | 563bd400d8a |
hex | 2d746efecdf |
3123631353055 has 32 divisors (see below), whose sum is σ = 3826145617920. Its totient is φ = 2447634309120.
The previous prime is 3123631353023. The next prime is 3123631353061. The reversal of 3123631353055 is 5503531363213.
It is not a de Polignac number, because 3123631353055 - 25 = 3123631353023 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3123631352999 and 3123631353017.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 37314607 + ... + 37398223.
It is an arithmetic number, because the mean of its divisors is an integer number (119567050560).
Almost surely, 23123631353055 is an apocalyptic number.
3123631353055 is a deficient number, since it is larger than the sum of its proper divisors (702514264865).
3123631353055 is a wasteful number, since it uses less digits than its factorization.
3123631353055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 84499.
The product of its (nonzero) digits is 364500, while the sum is 40.
The spelling of 3123631353055 in words is "three trillion, one hundred twenty-three billion, six hundred thirty-one million, three hundred fifty-three thousand, fifty-five".
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