Base | Representation |
---|---|
bin | 1001000101111010011… |
… | …10011011111000001101 |
3 | 1002212101112220101101102 |
4 | 10202331032123320031 |
5 | 20104310023321331 |
6 | 355304212152445 |
7 | 31366603635056 |
oct | 4427516337015 |
9 | 1085345811342 |
10 | 312412323341 |
11 | 110547680568 |
12 | 5066a308725 |
13 | 235ca52ac31 |
14 | 1119981172d |
15 | 81d72294cb |
hex | 48bd39be0d |
312412323341 has 2 divisors, whose sum is σ = 312412323342. Its totient is φ = 312412323340.
The previous prime is 312412323331. The next prime is 312412323343. The reversal of 312412323341 is 143323214213.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 232975155625 + 79437167716 = 482675^2 + 281846^2 .
It is a cyclic number.
It is not a de Polignac number, because 312412323341 - 238 = 37534416397 is a prime.
Together with 312412323343, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312412323343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156206161670 + 156206161671.
It is an arithmetic number, because the mean of its divisors is an integer number (156206161671).
Almost surely, 2312412323341 is an apocalyptic number.
It is an amenable number.
312412323341 is a deficient number, since it is larger than the sum of its proper divisors (1).
312412323341 is an equidigital number, since it uses as much as digits as its factorization.
312412323341 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 10368, while the sum is 29.
Adding to 312412323341 its reverse (143323214213), we get a palindrome (455735537554).
The spelling of 312412323341 in words is "three hundred twelve billion, four hundred twelve million, three hundred twenty-three thousand, three hundred forty-one".
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