Base | Representation |
---|---|
bin | 100011100001000110011000… |
… | …0100110000110111111011111 |
3 | 1111222011100010012100201010201 |
4 | 1013002030300212012333133 |
5 | 311422031140002041343 |
6 | 3024240143321444331 |
7 | 122543024352056065 |
oct | 10702146046067737 |
9 | 1458140105321121 |
10 | 312412441440223 |
11 | 905a9410687923 |
12 | 2b05775a6406a7 |
13 | 1054249cb88087 |
14 | 5720bb2aa6035 |
15 | 261b87054594d |
hex | 11c2330986fdf |
312412441440223 has 2 divisors, whose sum is σ = 312412441440224. Its totient is φ = 312412441440222.
The previous prime is 312412441440221. The next prime is 312412441440311. The reversal of 312412441440223 is 322044144214213.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 312412441440223 - 21 = 312412441440221 is a prime.
Together with 312412441440221, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312412441440221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156206220720111 + 156206220720112.
It is an arithmetic number, because the mean of its divisors is an integer number (156206220720112).
Almost surely, 2312412441440223 is an apocalyptic number.
312412441440223 is a deficient number, since it is larger than the sum of its proper divisors (1).
312412441440223 is an equidigital number, since it uses as much as digits as its factorization.
312412441440223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 147456, while the sum is 37.
Adding to 312412441440223 its reverse (322044144214213), we get a palindrome (634456585654436).
The spelling of 312412441440223 in words is "three hundred twelve trillion, four hundred twelve billion, four hundred forty-one million, four hundred forty thousand, two hundred twenty-three".
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