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3124134002981 is a prime number
BaseRepresentation
bin101101011101100100111…
…001011100000100100101
3102001122221021021222221002
4231131210321130010211
5402141211301043411
610351112442003045
7441465644605235
oct55354471340445
912048837258832
103124134002981
11aa4a35220492
1242558a1a6485
131987b2326484
14ab2cd2b5cc5
15563ec5de33b
hex2d764e5c125

3124134002981 has 2 divisors, whose sum is σ = 3124134002982. Its totient is φ = 3124134002980.

The previous prime is 3124134002867. The next prime is 3124134003017. The reversal of 3124134002981 is 1892004314213.

3124134002981 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2583381144100 + 540752858881 = 1607290^2 + 735359^2 .

It is a cyclic number.

It is not a de Polignac number, because 3124134002981 - 210 = 3124134001957 is a prime.

It is a super-2 number, since 2×31241340029812 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3124134902981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1562067001490 + 1562067001491.

It is an arithmetic number, because the mean of its divisors is an integer number (1562067001491).

Almost surely, 23124134002981 is an apocalyptic number.

It is an amenable number.

3124134002981 is a deficient number, since it is larger than the sum of its proper divisors (1).

3124134002981 is an equidigital number, since it uses as much as digits as its factorization.

3124134002981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41472, while the sum is 38.

The spelling of 3124134002981 in words is "three trillion, one hundred twenty-four billion, one hundred thirty-four million, two thousand, nine hundred eighty-one".