3124134003017 has 2 divisors, whose sum is σ = 3124134003018. Its totient is φ = 3124134003016.

The previous prime is 3124134002981. The next prime is 3124134003019. The reversal of 3124134003017 is 7103004314213.

3124134003017 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3119942864896 + 4191138121 = 1766336^2 + 64739^2 .

It is a cyclic number.

It is not a de Polignac number, because 3124134003017 - 2²⁶ = 3124066894153 is a prime.

It is a super-3 number, since 3×3124134003017³ (a number of 38 digits) contains 333 as substring.

Together with 3124134003019, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (3124134003019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1562067001508 + 1562067001509.

It is an arithmetic number, because the mean of its divisors is an integer number (1562067001509).

Almost surely, 2^{3124134003017} is an apocalyptic number.

It is an amenable number.

3124134003017 is a deficient number, since it is larger than the sum of its proper divisors (1).

3124134003017 is an equidigital number, since it uses as much as digits as its factorization.

3124134003017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 29.

The spelling of 3124134003017 in words is "three trillion, one hundred twenty-four billion, one hundred thirty-four million, three thousand, seventeen".