Base | Representation |
---|---|
bin | 1001000101111010101… |
… | …00111101110001001111 |
3 | 1002212101200010100101001 |
4 | 10202331110331301033 |
5 | 20104310443110043 |
6 | 355304313001131 |
7 | 31366624324306 |
oct | 4427524756117 |
9 | 1085350110331 |
10 | 312414035023 |
11 | 11054863a582 |
12 | 5066a9b31a7 |
13 | 235ca9aa06c |
14 | 11199b3943d |
15 | 81d746674d |
hex | 48bd53dc4f |
312414035023 has 2 divisors, whose sum is σ = 312414035024. Its totient is φ = 312414035022.
The previous prime is 312414034991. The next prime is 312414035027. The reversal of 312414035023 is 320530414213.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 312414035023 - 25 = 312414034991 is a prime.
It is a super-2 number, since 2×3124140350232 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 312414034982 and 312414035000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (312414035027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156207017511 + 156207017512.
It is an arithmetic number, because the mean of its divisors is an integer number (156207017512).
Almost surely, 2312414035023 is an apocalyptic number.
312414035023 is a deficient number, since it is larger than the sum of its proper divisors (1).
312414035023 is an equidigital number, since it uses as much as digits as its factorization.
312414035023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 28.
Adding to 312414035023 its reverse (320530414213), we get a palindrome (632944449236).
The spelling of 312414035023 in words is "three hundred twelve billion, four hundred fourteen million, thirty-five thousand, twenty-three".
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