Base | Representation |
---|---|
bin | 1110001101001111101100… |
… | …11010001101110110001111 |
3 | 11002121122121001112110220221 |
4 | 13012213312122031312033 |
5 | 13043324422342231112 |
6 | 150240040530252211 |
7 | 6403055534521114 |
oct | 706476632156617 |
9 | 132548531473827 |
10 | 31241431211407 |
11 | 9a5546450252a |
12 | 3606970127067 |
13 | 1458092465461 |
14 | 7a014419a90b |
15 | 3929dbe58e07 |
hex | 1c69f668dd8f |
31241431211407 has 2 divisors, whose sum is σ = 31241431211408. Its totient is φ = 31241431211406.
The previous prime is 31241431211363. The next prime is 31241431211411. The reversal of 31241431211407 is 70411213414213.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31241431211407 - 27 = 31241431211279 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31241431011407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15620715605703 + 15620715605704.
It is an arithmetic number, because the mean of its divisors is an integer number (15620715605704).
Almost surely, 231241431211407 is an apocalyptic number.
31241431211407 is a deficient number, since it is larger than the sum of its proper divisors (1).
31241431211407 is an equidigital number, since it uses as much as digits as its factorization.
31241431211407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 34.
The spelling of 31241431211407 in words is "thirty-one trillion, two hundred forty-one billion, four hundred thirty-one million, two hundred eleven thousand, four hundred seven".
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