312421024131141 has 4 divisors (see below), whose sum is σ = 416561365508192. Its totient is φ = 208280682754092.

The previous prime is 312421024131103. The next prime is 312421024131149. The reversal of 312421024131141 is 141131420124213.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 312421024131141 - 2¹⁸ = 312421023868997 is a prime.

It is a super-3 number, since 3×312421024131141³ (a number of 44 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 312421024131099 and 312421024131108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (312421024131149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52070170688521 + ... + 52070170688526.

It is an arithmetic number, because the mean of its divisors is an integer number (104140341377048).

Almost surely, 2^{312421024131141} is an apocalyptic number.

It is an amenable number.

312421024131141 is a deficient number, since it is larger than the sum of its proper divisors (104140341377051).

312421024131141 is a wasteful number, since it uses less digits than its factorization.

312421024131141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 104140341377050.

The product of its (nonzero) digits is 4608, while the sum is 30.

Adding to 312421024131141 its reverse (141131420124213), we get a palindrome (453552444255354).

The spelling of 312421024131141 in words is "three hundred twelve trillion, four hundred twenty-one billion, twenty-four million, one hundred thirty-one thousand, one hundred forty-one".