Search a number
-
+
313000131131 = 437279072817
BaseRepresentation
bin1001000111000000100…
…00101111101000111011
31002220220111222010002022
410203200100233220323
520112011013144011
6355442411025055
731420302134312
oct4434020575073
91086814863068
10313000131131
11110819461226
12507b313b18b
13236922481ac
1411213903279
15821db398db
hex48e042fa3b

313000131131 has 4 divisors (see below), whose sum is σ = 320279203992. Its totient is φ = 305721058272.

The previous prime is 313000131083. The next prime is 313000131163. The reversal of 313000131131 is 131131000313.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-313000131131 is a prime.

It is a super-2 number, since 2×3130001311312 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (313000101131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3639536366 + ... + 3639536451.

It is an arithmetic number, because the mean of its divisors is an integer number (80069800998).

Almost surely, 2313000131131 is an apocalyptic number.

313000131131 is a deficient number, since it is larger than the sum of its proper divisors (7279072861).

313000131131 is an equidigital number, since it uses as much as digits as its factorization.

313000131131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7279072860.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 313000131131 its reverse (131131000313), we get a palindrome (444131131444).

The spelling of 313000131131 in words is "three hundred thirteen billion, one hundred thirty-one thousand, one hundred thirty-one".

Divisors: 1 43 7279072817 313000131131