131131000313 has 2 divisors, whose sum is σ = 131131000314. Its totient is φ = 131131000312.

The previous prime is 131131000307. The next prime is 131131000327. The reversal of 131131000313 is 313000131131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 66730772329 + 64400227984 = 258323^2 + 253772^2 .

It is a cyclic number.

It is not a de Polignac number, because 131131000313 - 2¹⁸ = 131130738169 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131131000291 and 131131000300.

It is not a weakly prime, because it can be changed into another prime (131131000613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65565500156 + 65565500157.

It is an arithmetic number, because the mean of its divisors is an integer number (65565500157).

Almost surely, 2^131131000313 is an apocalyptic number.

It is an amenable number.

131131000313 is a deficient number, since it is larger than the sum of its proper divisors (1).

131131000313 is an equidigital number, since it uses as much as digits as its factorization.

131131000313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 131131000313 its reverse (313000131131), we get a palindrome (444131131444).

The spelling of 131131000313 in words is "one hundred thirty-one billion, one hundred thirty-one million, three hundred thirteen", and thus it is an aban number.