Base | Representation |
---|---|
bin | 1110001110111110101110… |
… | …10111101100110011110111 |
3 | 11002211100110021222200211221 |
4 | 13013133113113230303313 |
5 | 13100314012220001442 |
6 | 150323255501411211 |
7 | 6410265644050363 |
oct | 707372727546367 |
9 | 132740407880757 |
10 | 31301040000247 |
11 | 9a78773077886 |
12 | 3616426b69b07 |
13 | 14608a1b3a544 |
14 | 7a2d9aad62a3 |
15 | 39432a182467 |
hex | 1c77d75eccf7 |
31301040000247 has 2 divisors, whose sum is σ = 31301040000248. Its totient is φ = 31301040000246.
The previous prime is 31301040000161. The next prime is 31301040000289. The reversal of 31301040000247 is 74200004010313.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31301040000247 - 215 = 31301039967479 is a prime.
It is a super-2 number, since 2×313010400002472 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31301040000047) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15650520000123 + 15650520000124.
It is an arithmetic number, because the mean of its divisors is an integer number (15650520000124).
Almost surely, 231301040000247 is an apocalyptic number.
31301040000247 is a deficient number, since it is larger than the sum of its proper divisors (1).
31301040000247 is an equidigital number, since it uses as much as digits as its factorization.
31301040000247 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 25.
The spelling of 31301040000247 in words is "thirty-one trillion, three hundred one billion, forty million, two hundred forty-seven", and thus it is an aban number.
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