Base | Representation |
---|---|
bin | 1001000111000010000… |
… | …10101001001111011001 |
3 | 1002220221102120200211102 |
4 | 10203201002221033121 |
5 | 20112022340241441 |
6 | 355443555241145 |
7 | 31420521255311 |
oct | 4434102511731 |
9 | 1086842520742 |
10 | 313013212121 |
11 | 110825886165 |
12 | 507b75a91b5 |
13 | 23694b7821c |
14 | 1121554a441 |
15 | 821ed7069b |
hex | 48e10a93d9 |
313013212121 has 8 divisors (see below), whose sum is σ = 323118929664. Its totient is φ = 302908026960.
The previous prime is 313013212097. The next prime is 313013212157. The reversal of 313013212121 is 121212310313.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-313013212121 is a prime.
It is a super-3 number, since 3×3130132121213 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 313013212093 and 313013212102.
It is not an unprimeable number, because it can be changed into a prime (313013215121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1310471 + ... + 1530803.
It is an arithmetic number, because the mean of its divisors is an integer number (40389866208).
Almost surely, 2313013212121 is an apocalyptic number.
313013212121 is a gapful number since it is divisible by the number (31) formed by its first and last digit.
It is an amenable number.
313013212121 is a deficient number, since it is larger than the sum of its proper divisors (10105717543).
313013212121 is a wasteful number, since it uses less digits than its factorization.
313013212121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 266191.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 313013212121 its reverse (121212310313), we get a palindrome (434225522434).
The spelling of 313013212121 in words is "three hundred thirteen billion, thirteen million, two hundred twelve thousand, one hundred twenty-one".
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