Base | Representation |
---|---|
bin | 101101100011010100011… |
… | …010111000111101000111 |
3 | 102002020211222201121211221 |
4 | 231203110122320331013 |
5 | 402241323300312221 |
6 | 10354012344541211 |
7 | 442104516033055 |
oct | 55432432707507 |
9 | 12066758647757 |
10 | 3130300010311 |
11 | aa7609827011 |
12 | 42680b181807 |
13 | 199255907116 |
14 | ab7161791d5 |
15 | 5665dab9541 |
hex | 2d8d46b8f47 |
3130300010311 has 2 divisors, whose sum is σ = 3130300010312. Its totient is φ = 3130300010310.
The previous prime is 3130300010267. The next prime is 3130300010333. The reversal of 3130300010311 is 1130100030313.
It is a strong prime.
It is an emirp because it is prime and its reverse (1130100030313) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3130300010311 - 213 = 3130300002119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3130300010011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1565150005155 + 1565150005156.
It is an arithmetic number, because the mean of its divisors is an integer number (1565150005156).
Almost surely, 23130300010311 is an apocalyptic number.
3130300010311 is a deficient number, since it is larger than the sum of its proper divisors (1).
3130300010311 is an equidigital number, since it uses as much as digits as its factorization.
3130300010311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81, while the sum is 16.
Adding to 3130300010311 its reverse (1130100030313), we get a palindrome (4260400040624).
The spelling of 3130300010311 in words is "three trillion, one hundred thirty billion, three hundred million, ten thousand, three hundred eleven".
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