Base | Representation |
---|---|
bin | 1001000111000100011… |
… | …10100000101101001111 |
3 | 1002220222211000010000122 |
4 | 10203202032200231033 |
5 | 20112042433200421 |
6 | 355445545415155 |
7 | 31421152306634 |
oct | 4434216405517 |
9 | 1086884003018 |
10 | 313033100111 |
11 | 11083602a316 |
12 | 5080219a4bb |
13 | 2369901c674 |
14 | 1121804618b |
15 | 822199d2ab |
hex | 48e23a0b4f |
313033100111 has 2 divisors, whose sum is σ = 313033100112. Its totient is φ = 313033100110.
The previous prime is 313033100089. The next prime is 313033100119. The reversal of 313033100111 is 111001330313.
It is a strong prime.
It is an emirp because it is prime and its reverse (111001330313) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 313033100111 - 230 = 311959358287 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 313033100111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (313033100119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156516550055 + 156516550056.
It is an arithmetic number, because the mean of its divisors is an integer number (156516550056).
Almost surely, 2313033100111 is an apocalyptic number.
313033100111 is a deficient number, since it is larger than the sum of its proper divisors (1).
313033100111 is an equidigital number, since it uses as much as digits as its factorization.
313033100111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 313033100111 its reverse (111001330313), we get a palindrome (424034430424).
The spelling of 313033100111 in words is "three hundred thirteen billion, thirty-three million, one hundred thousand, one hundred eleven".
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