Base | Representation |
---|---|
bin | 100011100101101000000000… |
… | …1011010100001110011101111 |
3 | 1112001100210112222000001020011 |
4 | 1013023100001122201303233 |
5 | 312012223443023224403 |
6 | 3025434005523434051 |
7 | 122635663514530654 |
oct | 10713200132416357 |
9 | 1461323488001204 |
10 | 313034420133103 |
11 | 90819174413709 |
12 | 2b138201b25927 |
13 | 105890331171a6 |
14 | 5742d37d41c2b |
15 | 262cb24bd3a6d |
hex | 11cb4016a1cef |
313034420133103 has 2 divisors, whose sum is σ = 313034420133104. Its totient is φ = 313034420133102.
The previous prime is 313034420133073. The next prime is 313034420133107. The reversal of 313034420133103 is 301331024430313.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 313034420133103 - 221 = 313034418035951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (313034420133107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156517210066551 + 156517210066552.
It is an arithmetic number, because the mean of its divisors is an integer number (156517210066552).
Almost surely, 2313034420133103 is an apocalyptic number.
313034420133103 is a deficient number, since it is larger than the sum of its proper divisors (1).
313034420133103 is an equidigital number, since it uses as much as digits as its factorization.
313034420133103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23328, while the sum is 31.
Adding to 313034420133103 its reverse (301331024430313), we get a palindrome (614365444563416).
The spelling of 313034420133103 in words is "three hundred thirteen trillion, thirty-four billion, four hundred twenty million, one hundred thirty-three thousand, one hundred three".
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