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313103543315399 is a prime number
BaseRepresentation
bin100011100110001000001100…
…1011110100010101111000111
31112001121101222021110112022222
41013030100121132202233013
5312014342024042043044
63025525440533242555
7122643661454063534
oct10714203136425707
91461541867415288
10313103543315399
1190845515677651
122b14969319345b
13105926ca9c3ba5
145746414313d8b
15262e81d3468ee
hex11cc4197a2bc7

313103543315399 has 2 divisors, whose sum is σ = 313103543315400. Its totient is φ = 313103543315398.

The previous prime is 313103543315377. The next prime is 313103543315401. The reversal of 313103543315399 is 993513345301313.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 313103543315399 - 216 = 313103543249863 is a prime.

Together with 313103543315401, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 313103543315399.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (313103543315369) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156551771657699 + 156551771657700.

It is an arithmetic number, because the mean of its divisors is an integer number (156551771657700).

Almost surely, 2313103543315399 is an apocalyptic number.

313103543315399 is a deficient number, since it is larger than the sum of its proper divisors (1).

313103543315399 is an equidigital number, since it uses as much as digits as its factorization.

313103543315399 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5904900, while the sum is 53.

The spelling of 313103543315399 in words is "three hundred thirteen trillion, one hundred three billion, five hundred forty-three million, three hundred fifteen thousand, three hundred ninety-nine".