Base | Representation |
---|---|
bin | 1110001111010001100001… |
… | …10010011011010100011111 |
3 | 11002212022111111022112212012 |
4 | 13013220300302123110133 |
5 | 13101000143302111221 |
6 | 150332045023501435 |
7 | 6411103664435546 |
oct | 707506062332437 |
9 | 132768444275765 |
10 | 31311130113311 |
11 | 9a81a807400a4 |
12 | 361838215787b |
13 | 146181c3b9249 |
14 | 7a3676bd515d |
15 | 39471ade065b |
hex | 1c7a30c9b51f |
31311130113311 has 4 divisors (see below), whose sum is σ = 31311196717824. Its totient is φ = 31311063508800.
The previous prime is 31311130113299. The next prime is 31311130113337. The reversal of 31311130113311 is 11331103111313.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31311130113311 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31311130193311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32592050 + ... + 33538991.
It is an arithmetic number, because the mean of its divisors is an integer number (7827799179456).
Almost surely, 231311130113311 is an apocalyptic number.
31311130113311 is a deficient number, since it is larger than the sum of its proper divisors (66604513).
31311130113311 is an equidigital number, since it uses as much as digits as its factorization.
31311130113311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66604512.
The product of its (nonzero) digits is 243, while the sum is 23.
Adding to 31311130113311 its reverse (11331103111313), we get a palindrome (42642233224624).
The spelling of 31311130113311 in words is "thirty-one trillion, three hundred eleven billion, one hundred thirty million, one hundred thirteen thousand, three hundred eleven".
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