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313112200200000 = 263553538591721
BaseRepresentation
bin100011100110001100001110…
…1011101111011111101000000
31112001122020022120220211111120
41013030120131131323331000
5312020012241222400000
63025533431540312240
7122644416132303255
oct10714303535737500
91461566276824446
10313112200200000
1190849158216133
122b14b2aa3a2680
131059347a35b806
1457469d5d3142c
15262eb783496a0
hex11cc61d77bf40

313112200200000 has 672 divisors, whose sum is σ = 1040233442048640. Its totient is φ = 83114803200000.

The previous prime is 313112200199963. The next prime is 313112200200029. The reversal of 313112200200000 is 2002211313.

It is a super-3 number, since 3×3131122002000003 (a number of 44 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 181936199140 + ... + 181936200860.

It is an arithmetic number, because the mean of its divisors is an integer number (1547966431620).

Almost surely, 2313112200200000 is an apocalyptic number.

313112200200000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 313112200200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (520116721024320).

313112200200000 is an abundant number, since it is smaller than the sum of its proper divisors (727121241848640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

313112200200000 is an equidigital number, since it uses as much as digits as its factorization.

313112200200000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2973 (or 2943 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 313112200200000 its reverse (2002211313), we get a palindrome (313114202411313).

The spelling of 313112200200000 in words is "three hundred thirteen trillion, one hundred twelve billion, two hundred million, two hundred thousand".