Base | Representation |
---|---|
bin | 1001000111011001110… |
… | …01010101111000011001 |
3 | 1002221110021211020212122 |
4 | 10203230321111320121 |
5 | 20112424244200441 |
6 | 355515422151025 |
7 | 31425454631564 |
oct | 4435471257031 |
9 | 1087407736778 |
10 | 313212100121 |
11 | 110918079708 |
12 | 50852122475 |
13 | 236c713332b |
14 | 11233b1d4db |
15 | 823255a34b |
hex | 48ece55e19 |
313212100121 has 2 divisors, whose sum is σ = 313212100122. Its totient is φ = 313212100120.
The previous prime is 313212100073. The next prime is 313212100171. The reversal of 313212100121 is 121001212313.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 171260234896 + 141951865225 = 413836^2 + 376765^2 .
It is a cyclic number.
It is not a de Polignac number, because 313212100121 - 234 = 296032230937 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 313212100121.
It is not a weakly prime, because it can be changed into another prime (313212100171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156606050060 + 156606050061.
It is an arithmetic number, because the mean of its divisors is an integer number (156606050061).
Almost surely, 2313212100121 is an apocalyptic number.
It is an amenable number.
313212100121 is a deficient number, since it is larger than the sum of its proper divisors (1).
313212100121 is an equidigital number, since it uses as much as digits as its factorization.
313212100121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 313212100121 its reverse (121001212313), we get a palindrome (434213312434).
The spelling of 313212100121 in words is "three hundred thirteen billion, two hundred twelve million, one hundred thousand, one hundred twenty-one".
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