Base | Representation |
---|---|
bin | 11101001011000000… |
… | …001100001010111111 |
3 | 2222211221221221222222 |
4 | 131023000030022333 |
5 | 1003122204042002 |
6 | 22220054555555 |
7 | 2156134026416 |
oct | 351300141277 |
9 | 88757857888 |
10 | 31323112127 |
11 | 1231409782a |
12 | 60a2068bbb |
13 | 2c52532b98 |
14 | 173206447d |
15 | c34d821a2 |
hex | 74b00c2bf |
31323112127 has 2 divisors, whose sum is σ = 31323112128. Its totient is φ = 31323112126.
The previous prime is 31323112091. The next prime is 31323112133. The reversal of 31323112127 is 72121132313.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 31323112127 - 210 = 31323111103 is a prime.
It is a super-2 number, since 2×313231121272 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31323112096 and 31323112105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31323112147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15661556063 + 15661556064.
It is an arithmetic number, because the mean of its divisors is an integer number (15661556064).
Almost surely, 231323112127 is an apocalyptic number.
31323112127 is a deficient number, since it is larger than the sum of its proper divisors (1).
31323112127 is an equidigital number, since it uses as much as digits as its factorization.
31323112127 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1512, while the sum is 26.
The spelling of 31323112127 in words is "thirty-one billion, three hundred twenty-three million, one hundred twelve thousand, one hundred twenty-seven".
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