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3132313212120 = 23351747611274217
BaseRepresentation
bin101101100101001100011…
…010101001010011011000
3102002110001021220212112220
4231211030122221103120
5402304434140241440
610354544222504040
7442205433001101
oct55451432512330
912073037825486
103132313212120
11aa8452170364
12427091435020
131994b6a244b1
14ab8676ad3a8
155672a6d88d0
hex2d94c6a94d8

3132313212120 has 512 divisors, whose sum is σ = 10411767889920. Its totient is φ = 750671953920.

The previous prime is 3132313212113. The next prime is 3132313212121. The reversal of 3132313212120 is 212123132313.

It is a super-2 number, since 2×31323132121202 (a number of 26 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3132313212121) by changing a digit.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 742780252 + ... + 742784468.

It is an arithmetic number, because the mean of its divisors is an integer number (20335484160).

Almost surely, 23132313212120 is an apocalyptic number.

3132313212120 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 3132313212120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (5205883944960).

3132313212120 is an abundant number, since it is smaller than the sum of its proper divisors (7279454677800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3132313212120 is a wasteful number, since it uses less digits than its factorization.

3132313212120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4483 (or 4479 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 3132313212120 its reverse (212123132313), we get a palindrome (3344436344433).

It can be divided in two parts, 3132313 and 212120, that added together give a palindrome (3344433).

The spelling of 3132313212120 in words is "three trillion, one hundred thirty-two billion, three hundred thirteen million, two hundred twelve thousand, one hundred twenty".