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31331004143 = 311010677553
BaseRepresentation
bin11101001011011110…
…010010111011101111
32222212111210220210212
4131023132102323233
51003131214113033
622220540053035
72156261066255
oct351336227357
988774726725
1031331004143
111231859815a
1260a483417b
132c5406710a
14173311a5d5
15c358e0748
hex74b792eef

31331004143 has 4 divisors (see below), whose sum is σ = 32341681728. Its totient is φ = 30320326560.

The previous prime is 31331004139. The next prime is 31331004163. The reversal of 31331004143 is 34140013313.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 31331004143 - 22 = 31331004139 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31331004163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 505338746 + ... + 505338807.

It is an arithmetic number, because the mean of its divisors is an integer number (8085420432).

Almost surely, 231331004143 is an apocalyptic number.

31331004143 is a deficient number, since it is larger than the sum of its proper divisors (1010677585).

31331004143 is a wasteful number, since it uses less digits than its factorization.

31331004143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1010677584.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 31331004143 its reverse (34140013313), we get a palindrome (65471017456).

The spelling of 31331004143 in words is "thirty-one billion, three hundred thirty-one million, four thousand, one hundred forty-three".

Divisors: 1 31 1010677553 31331004143