3134413252535 has 4 divisors (see below), whose sum is σ = 3761295903048. Its totient is φ = 2507530602024.

The previous prime is 3134413252513. The next prime is 3134413252549. The reversal of 3134413252535 is 5352523144313.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3134413252535 - 2¹⁴ = 3134413236151 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3134413252492 and 3134413252501.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 313441325249 + ... + 313441325258.

It is an arithmetic number, because the mean of its divisors is an integer number (940323975762).

Almost surely, 2^{3134413252535} is an apocalyptic number.

3134413252535 is a deficient number, since it is larger than the sum of its proper divisors (626882650513).

3134413252535 is an equidigital number, since it uses as much as digits as its factorization.

3134413252535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 626882650512.

The product of its digits is 648000, while the sum is 41.

Adding to 3134413252535 its reverse (5352523144313), we get a palindrome (8486936396848).

The spelling of 3134413252535 in words is "three trillion, one hundred thirty-four billion, four hundred thirteen million, two hundred fifty-two thousand, five hundred thirty-five".