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313442321313997 is a prime number
BaseRepresentation
bin100011101000100101111101…
…0001110000011000011001101
31112002210210102022000222210101
41013101023322032003003031
5312040414333224021442
63030345225313411101
7123010313630415541
oct10721137216030315
91462723368028711
10313442321313997
1190966161a59177
122b1a327b269a91
13105b863a6794a5
145758991607a21
15263854a0a7cb7
hex11d12fa3830cd

313442321313997 has 2 divisors, whose sum is σ = 313442321313998. Its totient is φ = 313442321313996.

The previous prime is 313442321313857. The next prime is 313442321314009. The reversal of 313442321313997 is 799313123244313.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 312928281068841 + 514040245156 = 17689779^2 + 716966^2 .

It is a cyclic number.

It is not a de Polignac number, because 313442321313997 - 223 = 313442312925389 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (313442321311997) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156721160656998 + 156721160656999.

It is an arithmetic number, because the mean of its divisors is an integer number (156721160656999).

Almost surely, 2313442321313997 is an apocalyptic number.

It is an amenable number.

313442321313997 is a deficient number, since it is larger than the sum of its proper divisors (1).

313442321313997 is an equidigital number, since it uses as much as digits as its factorization.

313442321313997 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 8817984, while the sum is 55.

The spelling of 313442321313997 in words is "three hundred thirteen trillion, four hundred forty-two billion, three hundred twenty-one million, three hundred thirteen thousand, nine hundred ninety-seven".