Base | Representation |
---|---|
bin | 1001000111111101011… |
… | …10110110011111101011 |
3 | 1002222020010220012211112 |
4 | 10203332232312133223 |
5 | 20114032400340021 |
6 | 400005232020535 |
7 | 31436050264232 |
oct | 4437656663753 |
9 | 1088203805745 |
10 | 313511340011 |
11 | 110a60a84001 |
12 | 5091639174b |
13 | 2374412615c |
14 | 11261775b19 |
15 | 824d968d5b |
hex | 48febb67eb |
313511340011 has 2 divisors, whose sum is σ = 313511340012. Its totient is φ = 313511340010.
The previous prime is 313511340007. The next prime is 313511340047. The reversal of 313511340011 is 110043115313.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 313511340011 - 22 = 313511340007 is a prime.
It is not a weakly prime, because it can be changed into another prime (313511310011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 156755670005 + 156755670006.
It is an arithmetic number, because the mean of its divisors is an integer number (156755670006).
Almost surely, 2313511340011 is an apocalyptic number.
313511340011 is a deficient number, since it is larger than the sum of its proper divisors (1).
313511340011 is an equidigital number, since it uses as much as digits as its factorization.
313511340011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 23.
Adding to 313511340011 its reverse (110043115313), we get a palindrome (423554455324).
The spelling of 313511340011 in words is "three hundred thirteen billion, five hundred eleven million, three hundred forty thousand, eleven".
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