Base | Representation |
---|---|
bin | 110011001111100010… |
… | …1001010111100110001 |
3 | 101112001002112110110112 |
4 | 1212133011022330301 |
5 | 3300332014142223 |
6 | 122315245511105 |
7 | 10643654022035 |
oct | 1463705127461 |
9 | 345032473415 |
10 | 110043115313 |
11 | 4273a5192aa |
12 | 193b1272495 |
13 | a4b9414721 |
14 | 547cc081c5 |
15 | 2ce0cb2778 |
hex | 199f14af31 |
110043115313 has 4 divisors (see below), whose sum is σ = 112384458240. Its totient is φ = 107701772388.
The previous prime is 110043115289. The next prime is 110043115381. The reversal of 110043115313 is 313511340011.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 110043115313 - 218 = 110042853169 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (110043115813) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1170671393 + ... + 1170671486.
It is an arithmetic number, because the mean of its divisors is an integer number (28096114560).
Almost surely, 2110043115313 is an apocalyptic number.
It is an amenable number.
110043115313 is a deficient number, since it is larger than the sum of its proper divisors (2341342927).
110043115313 is an equidigital number, since it uses as much as digits as its factorization.
110043115313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2341342926.
The product of its (nonzero) digits is 540, while the sum is 23.
Adding to 110043115313 its reverse (313511340011), we get a palindrome (423554455324).
The spelling of 110043115313 in words is "one hundred ten billion, forty-three million, one hundred fifteen thousand, three hundred thirteen".
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