Base | Representation |
---|---|
bin | 1110010001010010010111… |
… | …11100101010110001001111 |
3 | 11010002221001102120002011022 |
4 | 13020221023330222301033 |
5 | 13103113331121301344 |
6 | 150423525131144355 |
7 | 6416103134456102 |
oct | 710511374526117 |
9 | 133087042502138 |
10 | 31380305259599 |
11 | 9aa934926638a |
12 | 36298688a50bb |
13 | 14681c498b27a |
14 | 7a6b5a052739 |
15 | 396418dba0ee |
hex | 1c8a4bf2ac4f |
31380305259599 has 2 divisors, whose sum is σ = 31380305259600. Its totient is φ = 31380305259598.
The previous prime is 31380305259571. The next prime is 31380305259661. The reversal of 31380305259599 is 99595250308313.
It is an a-pointer prime, because the next prime (31380305259661) can be obtained adding 31380305259599 to its sum of digits (62).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31380305259599 - 212 = 31380305255503 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31380305250599) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15690152629799 + 15690152629800.
It is an arithmetic number, because the mean of its divisors is an integer number (15690152629800).
Almost surely, 231380305259599 is an apocalyptic number.
31380305259599 is a deficient number, since it is larger than the sum of its proper divisors (1).
31380305259599 is an equidigital number, since it uses as much as digits as its factorization.
31380305259599 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 39366000, while the sum is 62.
The spelling of 31380305259599 in words is "thirty-one trillion, three hundred eighty billion, three hundred five million, two hundred fifty-nine thousand, five hundred ninety-nine".
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