Base | Representation |
---|---|
bin | 101101101010111000010… |
… | …100011001111111000101 |
3 | 102010000210210001202220211 |
4 | 231222320110121333011 |
5 | 402404440112430031 |
6 | 10401434115555421 |
7 | 442512635644054 |
oct | 55527024317705 |
9 | 12100723052824 |
10 | 3138418483141 |
11 | aaaaa5462897 |
12 | 4282b5bbbb71 |
13 | 199c4a85acb6 |
14 | abc8648239b |
15 | 569866b7bb1 |
hex | 2dab8519fc5 |
3138418483141 has 2 divisors, whose sum is σ = 3138418483142. Its totient is φ = 3138418483140.
The previous prime is 3138418483129. The next prime is 3138418483199. The reversal of 3138418483141 is 1413848148313.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1777766222241 + 1360652260900 = 1333329^2 + 1166470^2 .
It is an emirp because it is prime and its reverse (1413848148313) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3138418483141 - 29 = 3138418482629 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3138418481141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1569209241570 + 1569209241571.
It is an arithmetic number, because the mean of its divisors is an integer number (1569209241571).
Almost surely, 23138418483141 is an apocalyptic number.
It is an amenable number.
3138418483141 is a deficient number, since it is larger than the sum of its proper divisors (1).
3138418483141 is an equidigital number, since it uses as much as digits as its factorization.
3138418483141 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 884736, while the sum is 49.
The spelling of 3138418483141 in words is "three trillion, one hundred thirty-eight billion, four hundred eighteen million, four hundred eighty-three thousand, one hundred forty-one".
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