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314011100402 = 2157005550201
BaseRepresentation
bin1001001000111001000…
…01010010010011110010
31010000111222021200012122
410210130201102103302
520121043320203102
6400131003354242
731454326212506
oct4443441222362
91100458250178
10314011100402
1111119809741a
1250a35822982
13237c382616c
14112abca8306
15827c7860a2
hex491c8524f2

314011100402 has 4 divisors (see below), whose sum is σ = 471016650606. Its totient is φ = 157005550200.

The previous prime is 314011100393. The next prime is 314011100411. The reversal of 314011100402 is 204001110413.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 204001110413 = 974920925337.

It is an interprime number because it is at equal distance from previous prime (314011100393) and next prime (314011100411).

It can be written as a sum of positive squares in only one way, i.e., 278339601241 + 35671499161 = 527579^2 + 188869^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78502775099 + ... + 78502775102.

Almost surely, 2314011100402 is an apocalyptic number.

314011100402 is a deficient number, since it is larger than the sum of its proper divisors (157005550204).

314011100402 is a wasteful number, since it uses less digits than its factorization.

314011100402 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 157005550203.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 314011100402 its reverse (204001110413), we get a palindrome (518012210815).

The spelling of 314011100402 in words is "three hundred fourteen billion, eleven million, one hundred thousand, four hundred two".

Divisors: 1 2 157005550201 314011100402