Base | Representation |
---|---|
bin | 111011111001… |
… | …0010010111111 |
3 | 2012002100021121 |
4 | 1313302102333 |
5 | 31014314101 |
6 | 3041011411 |
7 | 530622355 |
oct | 167622277 |
9 | 65070247 |
10 | 31401151 |
11 | 167a8171 |
12 | a623b67 |
13 | 6675982 |
14 | 42557d5 |
15 | 2b540a1 |
hex | 1df24bf |
31401151 has 2 divisors, whose sum is σ = 31401152. Its totient is φ = 31401150.
The previous prime is 31401133. The next prime is 31401163. The reversal of 31401151 is 15110413.
It is a strong prime.
It is an emirp because it is prime and its reverse (15110413) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31401151 - 25 = 31401119 is a prime.
It is a super-3 number, since 3×314011513 (a number of 23 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31401101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15700575 + 15700576.
It is an arithmetic number, because the mean of its divisors is an integer number (15700576).
Almost surely, 231401151 is an apocalyptic number.
31401151 is a deficient number, since it is larger than the sum of its proper divisors (1).
31401151 is an equidigital number, since it uses as much as digits as its factorization.
31401151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60, while the sum is 16.
The square root of 31401151 is about 5603.6729918867. The cubic root of 31401151 is about 315.4872814327.
Adding to 31401151 its reverse (15110413), we get a palindrome (46511564).
The spelling of 31401151 in words is "thirty-one million, four hundred one thousand, one hundred fifty-one".
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