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3140202011315 = 5628040402263
BaseRepresentation
bin101101101100100010101…
…000000001101010110011
3102010012102002002101121212
4231230202220001222303
5402422113203330230
610402331111110335
7442605063455465
oct55544250015263
912105362071555
103140202011315
111000830196a16
124287133723ab
1319a173201805
14abdb52ac135
1556a3d06a895
hex2db22a01ab3

3140202011315 has 4 divisors (see below), whose sum is σ = 3768242413584. Its totient is φ = 2512161609048.

The previous prime is 3140202011299. The next prime is 3140202011339. The reversal of 3140202011315 is 5131102020413.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3140202011315 - 24 = 3140202011299 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 314020201127 + ... + 314020201136.

It is an arithmetic number, because the mean of its divisors is an integer number (942060603396).

Almost surely, 23140202011315 is an apocalyptic number.

3140202011315 is a deficient number, since it is larger than the sum of its proper divisors (628040402269).

3140202011315 is an equidigital number, since it uses as much as digits as its factorization.

3140202011315 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 628040402268.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 3140202011315 its reverse (5131102020413), we get a palindrome (8271304031728).

The spelling of 3140202011315 in words is "three trillion, one hundred forty billion, two hundred two million, eleven thousand, three hundred fifteen".

Divisors: 1 5 628040402263 3140202011315