3140344013 has 4 divisors (see below), whose sum is σ = 3141031740. Its totient is φ = 3139656288.

The previous prime is 3140344001. The next prime is 3140344021. The reversal of 3140344013 is 3104430413.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3104430413 = 7 ⋅443490059.

It can be written as a sum of positive squares in 2 ways, for example, as 172055689 + 2968288324 = 13117^2 + 54482^2 .

It is a cyclic number.

It is not a de Polignac number, because 3140344013 - 2¹⁸ = 3140081869 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 3140344013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3140344213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 336968 + ... + 346161.

It is an arithmetic number, because the mean of its divisors is an integer number (785257935).

Almost surely, 2^3140344013 is an apocalyptic number.

It is an amenable number.

3140344013 is a deficient number, since it is larger than the sum of its proper divisors (687727).

3140344013 is an equidigital number, since it uses as much as digits as its factorization.

3140344013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 687726.

The product of its (nonzero) digits is 1728, while the sum is 23.

The square root of 3140344013 is about 56038.7724080391. The cubic root of 3140344013 is about 1464.3978255665.

Adding to 3140344013 its reverse (3104430413), we get a palindrome (6244774426).

The spelling of 3140344013 in words is "three billion, one hundred forty million, three hundred forty-four thousand, thirteen".