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31405143317 is a prime number
BaseRepresentation
bin11101001111111001…
…000111010100010101
310000001200022120122012
4131033321013110111
51003304204041232
622232145114005
72161151212412
oct351771072425
9100050276565
1031405143317
1112356425aa9
126105628905
132c66524952
14173ccd9109
15c3c1879b2
hex74fe47515

31405143317 has 2 divisors, whose sum is σ = 31405143318. Its totient is φ = 31405143316.

The previous prime is 31405143293. The next prime is 31405143349. The reversal of 31405143317 is 71334150413.

It is an a-pointer prime, because the next prime (31405143349) can be obtained adding 31405143317 to its sum of digits (32).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 22607828881 + 8797314436 = 150359^2 + 93794^2 .

It is a cyclic number.

It is not a de Polignac number, because 31405143317 - 230 = 30331401493 is a prime.

It is a super-2 number, since 2×314051433172 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31405149317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15702571658 + 15702571659.

It is an arithmetic number, because the mean of its divisors is an integer number (15702571659).

Almost surely, 231405143317 is an apocalyptic number.

It is an amenable number.

31405143317 is a deficient number, since it is larger than the sum of its proper divisors (1).

31405143317 is an equidigital number, since it uses as much as digits as its factorization.

31405143317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15120, while the sum is 32.

The spelling of 31405143317 in words is "thirty-one billion, four hundred five million, one hundred forty-three thousand, three hundred seventeen".