Base | Representation |
---|---|
bin | 11101001111111010… |
… | …001111110010010111 |
3 | 10000001200212122211001 |
4 | 131033322033302113 |
5 | 1003304243041101 |
6 | 22232155324131 |
7 | 2161153560001 |
oct | 351772176227 |
9 | 100050778731 |
10 | 31405440151 |
11 | 12356609018 |
12 | 6105750647 |
13 | 2c665c9aa7 |
14 | 173cd75371 |
15 | c3c1e5901 |
hex | 74fe8fc97 |
31405440151 has 4 divisors (see below), whose sum is σ = 31783819032. Its totient is φ = 31027061272.
The previous prime is 31405440133. The next prime is 31405440167. The reversal of 31405440151 is 15104450413.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 31405440151 - 27 = 31405440023 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31405410151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 189189316 + ... + 189189481.
It is an arithmetic number, because the mean of its divisors is an integer number (7945954758).
Almost surely, 231405440151 is an apocalyptic number.
31405440151 is a deficient number, since it is larger than the sum of its proper divisors (378378881).
31405440151 is an equidigital number, since it uses as much as digits as its factorization.
31405440151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 378378880.
The product of its (nonzero) digits is 4800, while the sum is 28.
Adding to 31405440151 its reverse (15104450413), we get a palindrome (46509890564).
The spelling of 31405440151 in words is "thirty-one billion, four hundred five million, four hundred forty thousand, one hundred fifty-one".
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