Base | Representation |
---|---|
bin | 1110010010010001111101… |
… | …00111010111111101100111 |
3 | 11010020012011102120012221012 |
4 | 13021020332213113331213 |
5 | 13104143233433441403 |
6 | 150451332313212435 |
7 | 6421422066231053 |
oct | 711107647277547 |
9 | 133205142505835 |
10 | 31414441312103 |
11 | a011876169923 |
12 | 36343b4a0111b |
13 | 146b4a4bcc3c5 |
14 | 7a8677908c63 |
15 | 397265b90ed8 |
hex | 1c923e9d7f67 |
31414441312103 has 2 divisors, whose sum is σ = 31414441312104. Its totient is φ = 31414441312102.
The previous prime is 31414441312099. The next prime is 31414441312127. The reversal of 31414441312103 is 30121314441413.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31414441312103 - 22 = 31414441312099 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 31414441312103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31414441312153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15707220656051 + 15707220656052.
It is an arithmetic number, because the mean of its divisors is an integer number (15707220656052).
Almost surely, 231414441312103 is an apocalyptic number.
31414441312103 is a deficient number, since it is larger than the sum of its proper divisors (1).
31414441312103 is an equidigital number, since it uses as much as digits as its factorization.
31414441312103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 32.
Adding to 31414441312103 its reverse (30121314441413), we get a palindrome (61535755753516).
The spelling of 31414441312103 in words is "thirty-one trillion, four hundred fourteen billion, four hundred forty-one million, three hundred twelve thousand, one hundred three".
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