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31424642113 is a prime number
BaseRepresentation
bin11101010001000011…
…011111110001000001
310000010001000012221211
4131101003133301001
51003324202021423
622234123050121
72161506023254
oct352103376101
9100101005854
1031424642113
1112366433807
126110070941
132c6a590bb7
14174173309b
15c3dc3a10d
hex7510dfc41

31424642113 has 2 divisors, whose sum is σ = 31424642114. Its totient is φ = 31424642112.

The previous prime is 31424642111. The next prime is 31424642131. The reversal of 31424642113 is 31124642413.

Together with next prime (31424642131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 16877387569 + 14547254544 = 129913^2 + 120612^2 .

It is a cyclic number.

It is not a de Polignac number, because 31424642113 - 21 = 31424642111 is a prime.

Together with 31424642111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (31424642111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15712321056 + 15712321057.

It is an arithmetic number, because the mean of its divisors is an integer number (15712321057).

Almost surely, 231424642113 is an apocalyptic number.

It is an amenable number.

31424642113 is a deficient number, since it is larger than the sum of its proper divisors (1).

31424642113 is an equidigital number, since it uses as much as digits as its factorization.

31424642113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 13824, while the sum is 31.

The spelling of 31424642113 in words is "thirty-one billion, four hundred twenty-four million, six hundred forty-two thousand, one hundred thirteen".