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314255403701 is a prime number
BaseRepresentation
bin1001001001010110001…
…01001110101010110101
31010001010222222120022222
410210223011032222311
520122043340404301
6400211131532125
731463353600151
oct4445305165265
91101128876288
10314255403701
11111302a8a078
1250aa35ba045
1323832322925
14112d2500061
158293e4231b
hex492b14eab5

314255403701 has 2 divisors, whose sum is σ = 314255403702. Its totient is φ = 314255403700.

The previous prime is 314255403629. The next prime is 314255403703. The reversal of 314255403701 is 107304552413.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 301319753476 + 12935650225 = 548926^2 + 113735^2 .

It is a cyclic number.

It is not a de Polignac number, because 314255403701 - 226 = 314188294837 is a prime.

Together with 314255403703, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (314255403703) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157127701850 + 157127701851.

It is an arithmetic number, because the mean of its divisors is an integer number (157127701851).

Almost surely, 2314255403701 is an apocalyptic number.

It is an amenable number.

314255403701 is a deficient number, since it is larger than the sum of its proper divisors (1).

314255403701 is an equidigital number, since it uses as much as digits as its factorization.

314255403701 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 50400, while the sum is 35.

The spelling of 314255403701 in words is "three hundred fourteen billion, two hundred fifty-five million, four hundred three thousand, seven hundred one".