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314301131 is a prime number
BaseRepresentation
bin10010101110111…
…101101011001011
3210220102011002122
4102232331223023
51120430114011
651104321455
710534341554
oct2256755313
9726364078
10314301131
11151462101
128931328b
1350167301
142da5732b
151c8d63db
hex12bbdacb

314301131 has 2 divisors, whose sum is σ = 314301132. Its totient is φ = 314301130.

The previous prime is 314301107. The next prime is 314301133. The reversal of 314301131 is 131103413.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 314301131 - 222 = 310106827 is a prime.

It is a super-2 number, since 2×3143011312 = 197570401895758322, which contains 22 as substring.

Together with 314301133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (314301133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157150565 + 157150566.

It is an arithmetic number, because the mean of its divisors is an integer number (157150566).

Almost surely, 2314301131 is an apocalyptic number.

314301131 is a deficient number, since it is larger than the sum of its proper divisors (1).

314301131 is an equidigital number, since it uses as much as digits as its factorization.

314301131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 314301131 is about 17728.5400132103. The cubic root of 314301131 is about 679.9056465107.

Adding to 314301131 its reverse (131103413), we get a palindrome (445404544).

It can be divided in two parts, 314301 and 131, that added together give a cube (314432 = 683).

The spelling of 314301131 in words is "three hundred fourteen million, three hundred one thousand, one hundred thirty-one".