Base | Representation |
---|---|
bin | 1110010010110001000000… |
… | …10101100101000111100111 |
3 | 11010021210012022122212210112 |
4 | 13021120200111211013213 |
5 | 13104431404434400403 |
6 | 150503130513443235 |
7 | 6422552200026401 |
oct | 711304025450747 |
9 | 133253168585715 |
10 | 31431113200103 |
11 | a018950aa3061 |
12 | 363768827051b |
13 | 146cc30c311a6 |
14 | 7a93b9bb7b71 |
15 | 3978de6549d8 |
hex | 1c96205651e7 |
31431113200103 has 4 divisors (see below), whose sum is σ = 31431197436600. Its totient is φ = 31431028963608.
The previous prime is 31431113200099. The next prime is 31431113200117. The reversal of 31431113200103 is 30100231113413.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 31431113200103 - 22 = 31431113200099 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31431113200133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41556053 + ... + 42305646.
It is an arithmetic number, because the mean of its divisors is an integer number (7857799359150).
Almost surely, 231431113200103 is an apocalyptic number.
31431113200103 is a deficient number, since it is larger than the sum of its proper divisors (84236497).
31431113200103 is an equidigital number, since it uses as much as digits as its factorization.
31431113200103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 84236496.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 31431113200103 its reverse (30100231113413), we get a palindrome (61531344313516).
The spelling of 31431113200103 in words is "thirty-one trillion, four hundred thirty-one billion, one hundred thirteen million, two hundred thousand, one hundred three".
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