Base | Representation |
---|---|
bin | 101101101111011000011… |
… | …000111010101110101101 |
3 | 102010111021121020200020001 |
4 | 231233120120322232231 |
5 | 402444334341112140 |
6 | 10403553444224301 |
7 | 443043462644032 |
oct | 55573030725655 |
9 | 12114247220201 |
10 | 3143251504045 |
11 | 1002055590a44 |
12 | 42922469b091 |
13 | 19a53ac24593 |
14 | ac1c42b9389 |
15 | 56b6ab38e9a |
hex | 2dbd863abad |
3143251504045 has 4 divisors (see below), whose sum is σ = 3771901804860. Its totient is φ = 2514601203232.
The previous prime is 3143251504037. The next prime is 3143251504103. The reversal of 3143251504045 is 5404051523413.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 2153700067401 + 989551436644 = 1467549^2 + 994762^2 .
It is a cyclic number.
It is not a de Polignac number, because 3143251504045 - 23 = 3143251504037 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3143251503995 and 3143251504013.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 314325150400 + ... + 314325150409.
It is an arithmetic number, because the mean of its divisors is an integer number (942975451215).
Almost surely, 23143251504045 is an apocalyptic number.
It is an amenable number.
3143251504045 is a deficient number, since it is larger than the sum of its proper divisors (628650300815).
3143251504045 is an equidigital number, since it uses as much as digits as its factorization.
3143251504045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 628650300814.
The product of its (nonzero) digits is 144000, while the sum is 37.
The spelling of 3143251504045 in words is "three trillion, one hundred forty-three billion, two hundred fifty-one million, five hundred four thousand, forty-five".
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